Which of the numbers $\frac{3}{-4}, \frac{-5}{6}$ is greater?
To do: Find which of the following number is greater.
Answer:
$\frac{3}{-4} = \frac{-3}{4}; \frac{-5}{6}$ Taking the LCM of the denominators
LCM of 4 and 6 is 12
So $4\frac{-3}{4} = -\frac{3\times3}{4\times3} = \frac{-9}{12}$
$\frac{-5}{6} = -\frac{5\times2}{6\times2} = -\frac{10}{12}$
Of the two numbers $\frac{-9}{12}$ and $\frac{-10}{12}$, the greater number is $\frac{-9}{10}$
So of the two numbers $\frac{-3}{4}$ and $\frac{-5}{6}$, $\frac{-3}{4}$ is greater.
Related Articles
- Which is greater in each of the following:$(i)$. $\frac{2}{3},\ \frac{5}{2}$$(ii)$. $-\frac{5}{6},\ -\frac{4}{3}$$(iii)$. $-\frac{3}{4},\ \frac{2}{-3}$$(iv)$. $-\frac{1}{4},\ \frac{1}{4}$$(v)$. $-3\frac{2}{7\ },\ -3\frac{4}{5}$
- Which is greater:(i) $\frac{2}{7}$ of $\frac{3}{4}$ or $\frac{3}{5}$ of $\frac{5}{8}$
- Find the average of the rational numbers $\frac{4}{5}, \frac{2}{3}, \frac{5}{6}$.
- Simplify:(i) \( \frac{-3}{2}+\frac{5}{4}-\frac{7}{4} \)(ii) \( \frac{5}{3}-\frac{7}{6}+\frac{-2}{3} \)(iii) \( \frac{5}{4}-\frac{7}{6}-\frac{-2}{3} \)(iv) \( \frac{-2}{5}-\frac{-3}{10}-\frac{-4}{7} \)(v) \( \frac{5}{6}+\frac{-2}{5}-\frac{-2}{15} \)(vi) \( \frac{3}{8}-\frac{-2}{9}+\frac{-5}{36} \)
- Which of the following is a smaller fraction?a) \( \frac{4}{5} \)b) \( \frac{5}{3} \)c) \( \frac{5}{6} \)d) \( \frac{5}{2} \)
- Name the property used in the following:$[\frac{2}{3}+(\frac{-4}{5})]+\frac{1}{6}=\frac{2}{3}+[(\frac{-4}{5})+\frac{1}{6}]$
- Take away:\( \frac{6}{5} x^{2}-\frac{4}{5} x^{3}+\frac{5}{6}+\frac{3}{2} x \) from \( \frac{x^{3}}{3}-\frac{5}{2} x^{2}+\frac{3}{5} x+\frac{1}{4} \)
- Prove that:\( \frac{2^{\frac{1}{2}} \times 3^{\frac{1}{3}} \times 4^{\frac{1}{4}}}{10^{\frac{-1}{5}} \times 5^{\frac{3}{5}}} \p \frac{3^{\frac{4}{3}} \times 5^{\frac{-7}{5}}}{4^{\frac{-3}{5}} \times 6}=10 \)
- Simplify the following:\( 8 \frac{3}{5}-\left(6 \frac{1}{2}-4 \frac{1}{4}-3 \frac{3}{4}\right) \)
- Solve(a) \( \frac{2}{3}+\frac{1}{7} \)(b) \( \frac{3}{10}+\frac{7}{15} \)(c) \( \frac{4}{9}+\frac{2}{7} \)(d) \( \frac{5}{7}+\frac{1}{3} \)(e) \( \frac{2}{5}+\frac{1}{6} \)(f) \( \frac{4}{5}+\frac{2}{3} \)(g) \( \frac{3}{4}-\frac{1}{3} \)(h) \( \frac{5}{6}-\frac{1}{3} \)(i) \( \frac{2}{3}+\frac{3}{4}+\frac{1}{2} \)(j) \( \frac{1}{2}+\frac{1}{3}+\frac{1}{6} \)(k) \( 1 \frac{1}{3}+3 \frac{2}{3} \)(l) \( 4 \frac{2}{3}+3 \frac{1}{4} \)(m) \( \frac{16}{5}-\frac{7}{5} \)(n) \( \frac{4}{3}-\frac{1}{2} \)
- Look at the figures and write 's' or ' \( > \) ', '- ' between the given pairs of fractions.(a) \( \frac{1}{6} \square \frac{1}{3} \)(b) \( \frac{3}{4} \square \frac{2}{6} \)(c) \( \frac{2}{3} \square \frac{2}{4} \)(d) \( \frac{6}{6} \square \frac{3}{3} \)(e) \( \frac{5}{6} \square \frac{5}{5} \)"
- Find $n$ so that$(\frac{4}{5})^3)\times(\frac{4}{5})^{-6}=(\frac{4}{5})^{2n-1}$.
- Write four more rational numbers in each of the following patterns:$(i)$. $\frac{-3}{5},\ \frac{-6}{10},\ \frac{-9}{15},\ \frac{-12}{20}$........$(ii)$. $\frac{-1}{4},\ \frac{-2}{8},\ \frac{-3}{12}$.....$(iii)$. $\frac{-1}{6},\ \frac{2}{-12},\ \frac{3}{-18},\ \frac{4}{-24}$......$(iv)$. $\frac{-2}{3},\ \frac{2}{-3},\ \frac{4}{-6},\ \frac{6}{-9}$.....
- Compare the fractions and put an appropriate sign.(a) \( \frac{3}{6} \square \frac{5}{6} \)(b) \( \frac{1}{7} \square \frac{1}{4} \)(c) \( \frac{4}{5} \square \frac{5}{5} \)(d) \( \frac{3}{5} \square \frac{3}{7} \)
- Multiply the following fractions:(i) $\frac{2}{5}\times5\frac{1}{4}$(ii) $6\frac{2}{5}\times\frac{7}{9}$(iii) $\frac{3}{2}\times5\frac{1}{3}$(iv) $\frac{5}{6}\times2\frac{3}{7}$(v) $3\frac{2}{5}\times\frac{4}{7}$(vi) $2\frac{3}{5}\times3$(vii) $3\frac{4}{7}\times\frac{3}{5}$
Kickstart Your Career
Get certified by completing the course
Get Started