Which of the following is greater: $\frac{-11}{28}$ or $\frac{29}{-42}$.

Given: Fractions: $\frac{-11}{28}$ and $\frac{29}{-42}$.

To do: To find the greater fraction.

Solution:

Given fractions: $\frac{-11}{28}$ and $\frac{29}{-42}$.

We can write the given fraction as $-\frac{11}{28}$ and $-\frac{29}{42}$. To compare the given fractions we have to equalize  both the fraction.

On taking L.C.M. of the denominators of the given fractions:-

$28=2\times2\times7$

$42=2\times3\times7$

L.C.M. of $28$ and $42=2\times2\times3\times7=84$

Thus, $-\frac{11}{28}=-\frac{11\times3}{28\times3}=-\frac{33}{84}$

$-\frac{29}{42}=-\frac{29\times2}{42\times2}=-\frac{58}{84}$

On comparing both the fractions,

$-\frac{58}{84}<-\frac{33}{84}$

$\Rightarrow -\frac{29}{42}<-\frac{11}{28}$

$\Rightarrow \frac{29}{-42}<\frac{-11}{28}$

Thus, fraction $\frac{-11}{28}$ is greater than $\frac{29}{-42}$.

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Updated on: 10-Oct-2022

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