What should be added to $ \left(\frac{-13}{4}+\frac{-3}{8}\right) $ to get $ 1 ? $

Given:

$\frac{-13}{4}+\frac{-3}{8}$.

To do:

We have to find the number that should be added to $\frac{-13}{4}+\frac{-3}{8}$ to get 1.

Solution:

Let the required number be $x$.

This implies,

$\frac{-13}{4}+\frac{-3}{8}+x=1$

$\frac{2(-13)+(-3)}{8}+x=1$    (LCM of 4 and 8 is 8)

$\frac{-26-3}{8}+x=1$

$\frac{-29}{8}+x=1$

$x=1-(\frac{-29}{8})$

$x=1+\frac{29}{8}$

$x=\frac{1\times8+29}{8}$

$x=\frac{8+29}{8}$

$x=\frac{37}{8}$

The number that should be added to $\frac{-13}{4}+\frac{-3}{8}$ to get 1 is $\frac{37}{8}$.

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Updated on: 10-Oct-2022

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