What should be added to $(\frac{2}{3}+\frac{3}{5})$ to get $\frac{−12}{15}$?

Given :

The given numbers are $(\frac{2}{3}+\frac{3}{5})$ and $\frac{-12}{15}$.

To do :

We have to find the number that should be added to $(\frac{2}{3}+\frac{3}{5})$ to get $\frac{-12}{15}$.

Solution :

Let the number to be added to $(\frac{2}{3}+\frac{3}{5})$ to get $\frac{-12}{15}$ be $x$.

This implies,

$(\frac{2}{3}+\frac{3}{5})+x=\frac{-12}{15}$

$x =\frac{-12}{15} - (\frac{2}{3}+\frac{3}{5})$

$x =\frac{-12}{15} - (\frac{2(5)+3(3)}{15})$

$x=\frac{-12}{15}-\frac{19}{15}$

$x = \frac{-12-19}{15}$

$x = \frac{-31}{15}$

The number to be added to $(\frac{2}{3}+\frac{3}{5})$ to get $\frac{-12}{15}$ is $\frac{-31}{15}$.     

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Updated on: 10-Oct-2022

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