The velocity of a body of mass 10 kg increases from 4 m/s to 8 m/s when a force acts on it for 2 s. Calculate the applied force on the body.

 Here as given, mass of the body $m=10\ kg$

Initial velocity of the body $u=4\ m/s$

Final velocity $v=8\ m/s$

Time $t=2\ s$

Therefore, acceleration $a=\frac{v-u}{t}$

$=\frac{8-4}{2}$

$=2\ m/s^2$

Therefore, applied force $F=ma$

$=10\ kg\times2\ m/s^2$

$=20\ N$

Therefore, the applied force on the body is $20\ N$.

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Updated on: 10-Oct-2022

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