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The sum of the numerator and denominator of a fraction is 12. If the denominator is increased by 3, the fraction becomes $\frac{1}{2}$. Find the fraction.
Given:
The sum of the numerator and denominator of a fraction is 12. If the denominator is increased by 3, the fraction becomes $\frac{1}{2}$.
To do:
We have to find the original fraction.
Solution:
Let the denominator of the original fraction be $x$.
This implies,
The numerator of the original fraction$=12-x$.
The original fraction$=\frac{12-x}{x}$.
When the denominator is increased by 3, the fraction becomes $\frac{1}{2}$
This implies,
New fraction$=\frac{12-x}{x+3}$
According to the question,
$\frac{12-x}{x+3}=\frac{1}{2}$
$2(12-x)=1(x+3)$
$24-2x=x+3$
$x+2x=24-3$
$3x=21$
$x=\frac{21}{3}$
$x=7$
$\Rightarrow 12-x=12-7=5$.
Therefore, the original fraction is $\frac{5}{7}$.
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