The odometer of a car reads \( 2000 \mathrm{~km} \) at the start of a trip and \( 2400 \mathrm{~km} \) at the end of the trip. If the trip took \( 8 \mathrm{~h} \), calculate the average speed of the car in \( \mathrm{km} \mathrm{h}^{-1} \) and \( \mathrm{m} \mathrm{s}^{-1} \).

Odometer reads at start of the trip$=2000\ km$

Odometer reads at the end of the trip $=2400\ km$

Therefore, distance travelled by the car $=2400\ km-2000\ km=400\ km$

Time taken$=8\ h$

Therefore, speed of the car$=\frac{distance}{time}$

$=\frac{400\ km}{8\ h}$

$=50\ kmh^{-1}$

Now multiply the obtained speed by $\frac{5}{18}$ to convert the speed into $ms^{-1}$. 

Speed $=50\times\frac{5}{18}\ ms^{-1}$

$=13.89\ ms^{-1}$

Thus, the  speed of the car $=50\ kmh^{-1}=13.89\ ms^{-1}$

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Updated on: 10-Oct-2022

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