The odometer of a car reads $ 2000 \mathrm{~km} $ at the start of a trip and $ 2400 \mathrm{~km} $ at the end of the trip. If the trip took $ 8 \mathrm{~h} $, calculate the average speed of the car in $ \mathrm{km} \mathrm{h}^{-1} $ and $ \mathrm{m} \mathrm{s}^{-1} $.
Odometer reads at start of the trip$=2000\ km$
Odometer reads at the end of the trip $=2400\ km$
Therefore, distance travelled by the car $=2400\ km-2000\ km=400\ km$
Time taken$=8\ h$
Therefore, speed of the car$=\frac{distance}{time}$
$=\frac{400\ km}{8\ h}$
$=50\ kmh^{-1}$
Now multiply the obtained speed by $\frac{5}{18}$ to convert the speed into $ms^{-1}$.
Speed $=50\times\frac{5}{18}\ ms^{-1}$
$=13.89\ ms^{-1}$
Thus, the speed of the car $=50\ kmh^{-1}=13.89\ ms^{-1}$
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