The length of shadow of a tower on the play-ground is square root three times the height of the tower. The angle of elevation of the sun is:
$( A) \ 45^{o}$
$( B) \ 30^{o}$
$( C) \ 60^{o}$
$( D) \ 90^{o}$
Given: A tower whose shadow’s length is square root three times the height of the tower.
To do: To find out the angle of the elevation of sun.
Solution:
Let the tower is AB as shown in the figure, and BC is the shadow of the tower on the ground.
We have to find out $\angle \ ABC=?$
Let $\angle ABC=\theta $
$tan\theta =\frac{AB}{BC} =\frac{AB}{\sqrt{3} AB} =\frac{1}{\sqrt{3}} =tan30^{o}$
$\Rightarrow \theta =30^{o}$
Or $ \angle ABC=30^{o}$
$\therefore$ Option $( B)$ is correct.
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