If one of the complementary angles is twice the other, the two angles are 

a) $60^o, 30^o$

b) $20^o, 60^o$

c) $40^o, 40^o$

d) $10^o, 70^o$


Given:

One of the complementary angles is twice the other.

To do:

We have to find the two angles.

Solution:

Let the angles be $x$ and $2x$.

We know that,

Sum of two complementary angles is $90^o$.

This implies,

$x + 2x = 90^o$

$3x = 90^o$

$x=30^o$

The two angles are $30^o$ and $2(30)^o=60^o$.

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Updated on: 10-Oct-2022

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