Multiply the binomials: $( 4 a+3b)$ and $( 6b-5a)$.

Given: Binomials: $( 4 a+3b)$ and $( 6b-5a)$.

To do: To multiply the binomials: $( 4a+3b)$ and $( 6b-5a)$.

Solution:

Given binomials: $( 4a+3b)$ and $( 6b-5a)$

Therefore, $( 4a+3b)( 6b-5a)=4a\times6b-5a\times4a+3b\times6b-5a\times3b$

$=24ab-20a^2+18b^2-15ab$

$=9ab-20a^2+18b^2$

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Updated on: 10-Oct-2022

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