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How many 6 digits numbers are there?
Given :
The given statement is 6 digit numbers.
To do :
We have to find the number of 6 digit numbers.
Solution :
The least 6-digit number $= 100,000$
The greatest 6-digit number $= 999,999$
We can consider it as an arithmetic progression, first term: $a= 100,000$.
Last term $= 999,999$
common difference : d $= 1$
Formula for nth term $= a+ (n-1)d$
$999,999 = a+ (n-1)d$
$999,999 = 100,000 + (n-1)$
$n = 900,000$
Therefore, the number of 6 digit numbers is 900000.
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