Find the value of a if:

A) a $+$ ($-$ 32) = 0
B) a $-$ ($-$ 3) = 0

Given: a $+$ ($-$ 32) = 0 and a $-$ ($-$ 3) = 0

To find: Value of a in both  cases.

Solution: 

A) a $+$ ($-$ 32) = 0

We know that ($+$) $\times$ ($-$) = ($-$), So,

a $-$ 32 = 0

a = 32

So, value of a is 32.

B) a $-$ ($-$ 3) = 0

We know that ($-$) $\times$ ($-$) = ($+$), So,

a $+$ 3 = 0

a = $\mathbf{-}$ 3

So, the value of a is -3.

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Updated on: 10-Oct-2022

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