Find the smallest value of a, if the number
$6a4231$ is divisible by 3.
Given number $6a4231$
To find the smallest value of a, if the number
$6a4231$ is divisible by 3
Solution:
To be divisible by 3 the sum of the digits of $6a4231$ should be divisible by 3, that is
$6 + a + 4 + 2 + 3 + 1 = 16 + a$ should be divisible by 3. Smallest value of a = 2 makes 16 + 2 = 18 divisible by 3
So the required value of a = 2
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