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Determine the smallest 3-digit number which is exactly divisible by 6,8 and 12.
Given :
The given numbers are 6, 8, 12.
To do :
We have to find the smallest three digit number which is divisible by 6, 8, 12.
Solution :
The smallest 3-digit which is exactly divisible by 6,8 and 12 will be a multiple of LCM of 6,8 and 12.
LCM of 6,8 and 12 is,
$6 = 2\times3$
$8 = 2\times2\times2$
$12 = 2\times2\times3$
$LCM = 2\times2\times2\times3 = 24$
Multiples of 24 are 24, $24\times2=48,......., 24\times5=120,.....$
Therefore, the smallest 3-digit which is exactly divisible by 6, 8 and 12 is 120.
Updated on: 10-Oct-2022
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