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Replace m by smallest whole number to make the number resulting number divisible
46 m 46 (by 3)
Given:
The given number is 4 6m4 6
To do: Replace number m by a number so that the resultant number should be divisible by 3
Solution:
So, the sum of all numbers should be a multiple of '3'.
$4 + 6 + 4 + 6 = 20$
The sum of numbers except is $20$
The next number which is divisible by $3$ after $20$ is $21$
So, $20 + 1 = 21$
Therefore, m = 1
So the number is 4 6 1 4 6
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