Find the smallest square number divisible by each one of them number 8,9and 10


Given: Numbers $8,\ 9$ and $10$.

To do: To find the smallest square number divisible by each one of the number $8,\  9$ and $10$.

Solution:



L.C.M. of $8,\ 9,\ 10$ is $2\times2\times2\times3\times3\times5=360$

Since $2$ and $5$ are not in pairs multiply by $2$ and $5$ to make it a perfect square.

The required number$=360\times2\times5=3600$

The smallest square number divisible by $8,\ 9,\ 10=3600$. 

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Updated on: 10-Oct-2022

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