Find the product of the following.
$(3-8y+6y^2)$ and $(4-7y-2y^2)$

Given:

$(3-8y+6y^2)$ and $(4-7y-2y^2)$.

To do:

We have to find the product of the given terms.

Solution:

$(3-8y+6y^2)\times(4-7y-2y^2)=3(4-7y-2y^2)-8y(4-7y-2y^2)+6y^2(4-7y-2y^2)$

$=12-21y-6y^2-32y+56y^2+16y^3+24y^2-42y^3-12y^4$

$=-12y^4-26y^3+74y^2-53y+12$

Therefore,  $(3-8y+6y^2)\times(4-7y-2y^2)=-12y^4-26y^3+74y^2-53y+12$.

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Updated on: 10-Oct-2022

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