Find the nature of roots:$6k+\frac{17}{k} = \frac{29}{2}$

Given :

The given expression is $6k+\frac{17}{k} = \frac{29}{2}$.

To find :

We have to find the nature of the roots.

Solution :

$6k+\frac{17}{k} = \frac{29}{2}$

$6k(k)+17= \frac{29}{2} (k)$

$2(6k^2)+17(2) = 29k$

$12k^2+34=29k$

$12k^2-29k+34=0$

Discriminant $= (-29)^2-4(12)(34)$

                        $= 841-1632$

                        $= -791<0$

Therefore, the given equation does not have real roots.

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Updated on: 10-Oct-2022

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