Solve:$\frac{17}{9}-\frac{2}{15}+\frac{11}{18}$

To do: Solve the expression$\frac{17}{9}-\frac{2}{15}+\frac{11}{18}$

Solution:

To add unlike fractions, first we have to convert them as like fractions with same denominator.

Make the denominators the same by finding the Least Common Multiple (LCM) of their denominators.

LCM of denominators 9, 15, 18 is 90.

Multiply the numerator and denominator of the fraction with (LCM ÷ denominator) to make denominators equal.

• $\frac{17}{9}$ should be multiplied with $\frac{90}{9}$ =10
• $\frac{2}{15}$ should be multiplied with $\frac{90}{15}$ =6
• $\frac{11}{18}$ should be multiplied with $\frac{90}{18}$ =5

$\frac{17}{9}-\frac{2}{15}+ \frac{11}{18}=\frac{17\times10}{9\times10}\frac{2\times6}{15\times6}+\frac{11\times5}{18\times5}$

$\frac{170}{90}\frac{12}{90}+\frac{55}{90}$ 

Now denominators are same, so we can operate directly

$\frac{170-12+55}{90}$ =$\frac{213}{90}$

Therefore the value of the expression is$\frac{213}{90}$

$\frac{17}{9}-\frac{2}{15}+\frac{11}{18}=\frac{17\times 10}{9\times 10}-\frac{2\times 6}{15\times 6}+\frac{11\times 5}{18\times 5}$\frac{17}{9}-\frac{2}{15}+\frac{11}{18} = \frac{17\times{10}}{9\times{10}}-\frac{2\times{6}}{15\times{6}}+\frac{11\times{5}}{18\times{5}}

Tutorialspoint

Updated on: 10-Oct-2022

36 Views

Kickstart Your Career

Get certified by completing the course

Get Started