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Find the LCM and HCF of the following pairs of integers and verify that LCM $\times$ HCF $=$ product of two numbers:
(i) 26 and 91
(ii) 510 and 92
(iii) 336 and 54.
To do:
Here we have to find the LCM and HCF of the given pairs of integers and then verify that LCM $\times$ HCF $=$ Product of the numbers.
Solution:
Calculating LCM and HCF using prime factorization method:
Writing the numbers as a product of their prime factors:
(i) Prime factorisation of 26:
- $2\ \times\ 13\ =\ 2^1\ \times\ 13^1$
Prime factorisation of 91:
- $7\ \times\ 13\ =\ 7^1\ \times\ 13^1$
Multiplying the highest power of each prime number these values together:
$2^1\ \times\ 13^1\ \times\ 7^1\ =\ 182$
LCM(26, 91) $=$ 182
Multiplying all common prime factors:
$13^1\ =\ 13$
HCF(26, 91) $=$ 13
Now, verifying that LCM $\times$ HCF $=$ Product of the integers:
LCM $\times$ HCF $=$ Product of the integers
182 $\times$ 13 $=$ 26 $\times$ 91
2366 $=$ 2366.
(ii) Prime factorisation of 510:
- $2\ \times\ 3\ \times\ 5\ \times\ 17\ =\ 2^1\ \times\ 3^1\ \times\ 5^1\ \times\ 17^1$
Prime factorisation of 92:
- $2\ \times\ 2\ \times\ 23\ =\ 2^2\ \times\ 23^1$
Multiplying the highest power of each prime number these values together:
$2^2\ \times\ 3^1\ \times\ 5^1\ \times\ 17^1\ \times\ 23^1\ =\ 23460$
LCM(510, 92) $=$ 23460
Multiplying all common prime factors:
$2^1\ =\ 2$
HCF(510, 92) $=$ 2
Now, verifying that LCM $\times$ HCF $=$ Product of the integers:
LCM $\times$ HCF $=$ Product of the integers
23460 $\times$ 2 $=$ 510 $\times$ 92
46920 $=$ 46920.
(iii) Prime factorisation of 336:
- $2\ \times\ 2\ \times\ 2\ \times\ 2\ \times\ 3\ \times\ 7\ =\ 2^4\ \times\ 3^1\ \times\ 7^1$
Prime factorisation of 54:
- $2\ \times\ 3\ \times\ 3\ \times\ 3\ =\ 2^1\ \times\ 3^3$
Multiplying the highest power of each prime number these values together:
$2^4\ \times\ 3^3\ \times\ 7^1\ =\ 3024$
LCM(336, 54) $=$ 3024
Multiplying all common prime factors:
$2^1\ \times\ 3^1\ =\ 6$
HCF(336, 54) $=$ 6
Now, verifying that LCM $\times$ HCF $=$ Product of the integers:
LCM $\times$ HCF $=$ Product of the integers
3024 $\times$ 6 $=$ 336 $\times$ 54
18144 $=$ 18144.