Find:10th term of the A.P. $-40, -15, 10, 35, ……..$

Given:

Given A.P. is $-40, -15, 10, 35, ……..$

To do:

We have to find the 10th term of the given A.P.

Solution:

Here,

$a_1=-40, a_2=-15, a_3=10, a_4=35$

Common difference $d=a_2-a_1=-15-(-40)=-15+40=25$

We know that,

nth term $a_n=a+(n-1)d$

Therefore,

10th term $a_{10}=-40+(10-1)(25)$

$=-40+9\times25$

$=-40+225$

$=185$

The 10th term of the given A.P. is $185$.  

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Updated on: 10-Oct-2022

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