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Find the 8th term from the end of the A.P. $7, 10, 13, …, 184$.
Given:
Given A.P. is $7, 10, 13, …, 184$.
To do:
We have to find the 8th term from the end of the given arithmetic progression.
Solution:
In the given A.P.,
$a_1=7, a_2=10, a_3=13$
First term $a_1 = a= 7$, last term $l = 184$
Common difference $d = a_2-a_1 = 10 - 7 = 3$
We know that,
nth term from the end is given by $l - (n - 1 ) d$.
Therefore,
8th term from the end $= 184 - (8 - 1) \times 3 = 184 - 7 \times 3 = 184 - 21 = 163$.
The 8th term from the end of the given A.P. is $163$.  
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