Factorize the expressions: $y^2+2y-48$.


Given: The expression: $y^2+2y-48$.

To do: To factorize the expression: $y^2+2y-48$.

Solution:

As given 

$y^2+2y-48$

$=y^2+8y-6y-48$

$=y(y+8)-6(y+8)$

$=(y+8) (y-6)$

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Updated on: 10-Oct-2022

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