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Factorize the expressions: $y^2+2y-48$.
Given: The expression: $y^2+2y-48$.
To do: To factorize the expression: $y^2+2y-48$.
Solution:
As given
$y^2+2y-48$
$=y^2+8y-6y-48$
$=y(y+8)-6(y+8)$
$=(y+8) (y-6)$
Updated on: 10-Oct-2022
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