Factorize:$7(x-2y)^2 - 25(x-2y) +12$

Given :

To do :

We have to factorize the given expression.

Solution :

$7(x-2 y)^{2}-25(x-2 y)+12$

Let $x-2 y=a$

This implies,

$7(x-2 y)^{2}-25(x-2 y)+12=7 a^{2}-25 a+12$

$=7 a^{2}-21 a-4 a+12$

$=7 a(a-3)-4(a-3)$

$=(a-3)(7 a-4)$

Therefore,

$7(x-2 y)^{2}-25(x-2 y)+12=(x-2 y-3)[7 (x-2 y)-4]$

$=(x-2 y-3)(7x-14 y-4)$

Hence, $7(x-2 y)^{2}-25(x-2 y)+12=(x-2 y-3)(7x-14 y-4)$.

Tutorialspoint

Updated on: 10-Oct-2022

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