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Factorize:$x^3 + 8y^3 + 6x^2y + 12xy^2$
Given:
$x^3 + 8y^3 + 6x^2y + 12xy^2$
To do:
We have to factorize the given expression.
Solution:
We know that,
$(a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3$
$(a - b)^3 = a^3 - b^3 - 3ab(a - b)$
Therefore,
$x^3 + 8y^3 + 6x^2y + 12xy^2 = (x)^3 + (2y)^3 + 3 \times x^2 \times 2y + 3 \times x \times (2y)^2$
$= (x + 2y)^3$
$= (x + 2y) (x + 2y) (x + 2y)$
Hence, $x^3 + 8y^3 + 6x^2y + 12xy^2 = (x + 2y) (x + 2y) (x + 2y)$.
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