Expand: $x^2-(2y-3)^2$.

Given:

$x^2-(2y-3)^2$.

To do:

We have to expand $x^2-(2y-3)^2$.

Solution:

We know that,

$(a-b)^2=a^2-2ab+b^2$

Therefore,

$x^2-(2y-3)^2=x^2-[(2y)^2-2(2y)(3)+3^2]$ $=x^2-[4y^2-12y+9] $

$=x^2-4y^2+12y-9$

The expanded form of $x^2-(2y-3)^2$ is $x^2-4y^2+12y-9$.

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Updated on: 10-Oct-2022

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