- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- MS Excel
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP
- Physics
- Chemistry
- Biology
- Mathematics
- English
- Economics
- Psychology
- Social Studies
- Fashion Studies
- Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Factorize $(a^2-b^2-c^2) ^2-4b^2c^2$.
Given: Polynomial: $(a^2-b^2-c^2)^2-4b^2c^2$.
To do: To factorize $(a^2-b^2-c^2)^2-4b^2c^2$.
Solution:
$(a^2-b^2-c^2)^2-4b^2c^2$
$=(a^2-b^2-c^2)^2-(2bc)^2$
$=(a^2-b^2-c^2-2bc)(a^2-b^2-c^2+2bc)$
$=(a^2-(b^2+c^2+2bc))(a^2-( b^2-2bc+c^2))$
$=(a^2-(b+c)^2)(a^2-(b-c)^2)$
$=[(a-(b+c))(a+(b+c))][(a-(b-c))(a+(b-c))]$
$=(a-b-c)(a+b+c)(a-b+c)(a+b-c)$
Advertisements