Factorize:$ 6 a b-b^{2}+12 a c-2 b c $

Given :

\( 6 a b-b^{2}+12 a c-2 b c \)

To do :

We have to factorize the given expression.

Solution :

$6ab - b^2 + 12ac - 2bc = 6ab + 12ac - b^2 - 2bc$

$= 6a(b + 2c) - b(b + 2c)$

$= (b + 2c) (6a - b)$

Hence, $6ab - b^2 + 12ac - 2bc = (b + 2c) (6a - b)$. 

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Updated on: 10-Oct-2022

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