Factorize:$(a – b + c)^2 + (b – c + a)^2 + 2(a – b + c) (b – c + a)$

Given :

$(a – b + c)^2 + (b – c + a)^2 + 2(a – b + c) (b – c + a)$

To do :

We have to factorize the given expression.

Solution :

$(a - b + c)^2 + ( b - c+a)^2 + 2(a - b + c) (b - c + a) = [(a - b + c) + (b - c + a)]^2$

$= (2a)^2$

$= 4a^2$

Hence, $(a - b + c)^2 + ( b - c+a)^2 + 2(a - b + c) (b - c + a) = 4a^2$.

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Updated on: 10-Oct-2022

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