Evaluate the following:
$ \cos 48^{\circ}-\sin 42^{\circ} $

Given:

\( \cos 48^{\circ}-\sin 42^{\circ} \)

To do:

We have to evaluate \( \cos 48^{\circ}-\sin 42^{\circ} \).

Solution:  

We know that,

$sin\ (90^{\circ}- \theta) = cos\ \theta$

Therefore,

$\cos 48^{\circ}-\sin 42^{\circ}=\cos 48^{\circ}-\sin (90^{\circ}-48^{\circ})$

$=\cos 48^{\circ}-\cos 48^{\circ}$

$=0$

Therefore, $\cos 48^{\circ}-\sin 42^{\circ}=0$.   

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

27 Views

Kickstart Your Career

Get certified by completing the course

Get Started