Draw a right triangle in which the sides (other than the hypotenuse) are of lengths
$ 4 \mathrm{~cm} $ and $ 3 \mathrm{~cm} $. Now, construct another triangle whose sides are $ \frac{5}{3} $ times the corresponding sides of the given triangle.

Given:

A right triangle in which the sides (other than the hypotenuse) are of lengths

\( 4 \mathrm{~cm} \) and \( 3 \mathrm{~cm} \).

To do:

We have to draw a right triangle in which the sides (other than the hypotenuse) are of lengths

\( 4 \mathrm{~cm} \) and \( 3 \mathrm{~cm} \). Now, construct another triangle whose sides are \( \frac{5}{3} \) times the corresponding sides of the given triangle.

Solution:

Steps of construction:

(i) Draw right angled triangle $ABC$ with right angle at $B$ and $BC = 4\ cm$ and $BA = 3\ cm$.

(ii) Draw a line $BY$ making an acute angle with $BC$ and cut off five equal parts.

(iii) Join $B_4C$ and draw $B_3C’\ \parallel\ B_5C$ and $C’A’$ parallel to $CA$.

$BC’A’$ is the required triangle.