Candidates of four schools appear in a mathematics test. The data were as follows :
SchoolsNo. of CandidatesAverage Score
I6075
II4880
IIINot available 55
IV4050.
If the average score of the candidates of all the four schools is 66, find the number of candidates that appeared from school III.


Given:

The average score of the candidates of all the four schools is 66.

To do:

We have to find the number of candidates that appeared from school III.

Solution:

Let the number of candidates that appeared from school III be $p$.

Therefore,

SchoolsNo.of candidates ($f$)Average Score ($x$)Total Score ($f \times\ x$)
II60754500
II48803840
III$p$55$55p$
IV40502000
Total$148+p$$10340+55p$

 We know that,

Mean$=\frac{\sum fx}{\sum f}$

Therefore,

Mean $66=\frac{10340+55p}{148+p}$

$66(148+p)=10340+55p$

$9768+66p=10340+55p$

$66p-55p=10340-9768$

$11p=572$

$p=\frac{572}{11}$

$p=52$

The number of candidates that appeared from school III is $52$.

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Updated on: 10-Oct-2022

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