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An object is placed at a distance of 10 cm from a convex mirror of focal length 5 cm.(i) Draw a ray-diagram showing the formation image(ii) State two characteristics of the image formed(iii) Calculate the distance of the image from mirror.
(i) Ray Diagram -
(ii) The two characteristics of the image formed are:
1. It is virtual and erect. (behind the mirror and upright)
2. It is smaller than the object.
(iii) Given:
Convex Mirror
Distance of the object, $u$ = $-$10 cm
Focal length of the mirror, $f$ = 5 cm
To find: Distance of the image from the mirror, $v$.
Solution:
From the mirror formula, we know that-
$\frac {1}{f}=\frac {1}{v}+\frac {1}{u}$
Substituting the given values we get-
$\frac {1}{5}=\frac {1}{v}+\frac {1}{(-10)}$
$\frac {1}{5}=\frac {1}{v}-\frac {1}{10}$
$\frac {1}{5}+\frac {1}{10}=\frac {1}{v}$
$\frac {1}{v}=\frac {2+1}{10}$
$\frac {1}{v}=\frac {3}{10}$
$v=\frac {10}{3}$
$v=+0.3cm$
Thus, the distance of the image $v$ is 0.3 cm from the mirror, and the positive sign implies that the image forms behind the mirror (on the right).