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A particle moves over three quarters of a circle of radius $r$ in time $t$. Find the speed of the particle.
As given, a particle moves over three quarters of a circle of radius $r$.
The motion of the particle has been shown in the diagram below:
Distance travelled $\frac{3}{4}$of the circumference of the circle
$=\frac{3}{4}\times2\pi r$
$=\frac{3}{2}\pi r$
Therefore, speed$=\frac{distance}{time}$$
$=\frac{\frac{3}{2}\pi r}{t}$
$=\frac{3}{2t}\pi r$
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