A conical pit of top diameter $ 3.5 \mathrm{~m} $ is $ 12 \mathrm{~m} $ deep. What is its capacity in kilolitres?
Given:
A conical pit of top diameter $3.5\ m$ is $12\ m$ deep.
To do:
We have to find its capacity in kilolitres.
Solution:
Diameter of the top of the conical pit $= 3.5\ m$
This implies,
Radius of the top of the pit $(r)=\frac{3.5}{2}$
$=1.75 \mathrm{~m}$
Depth of the pit $(h)=12 \mathrm{~m}$
Therefore,
Volume of the pit $=\frac{1}{3} \pi r^{2} h$
$=\frac{1}{3} \times \frac{22}{7} \times 1.75 \times 1.75 \times 12$
$=38.5 \mathrm{~m}^{3}$
The capacity of the pit in kilolitres $=38.5$ kilolitres (Since $1\ m^3 = 1000\ L$ and $1\ m^3 = 1\ kL$)
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