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The inner diameter of a circular well is $3.5\ m$. It is $10\ m$ deep. Find inner curved surface area.
Given:
The inner diameter of a circular well is $3.5\ m$. It is $10\ m$ deep.
To do:
We have to find the inner curved surface area.
Solution:
Inner diameter of the well $= 3.5\ m$
This implies,
Radius $(r)=\frac{3.5}{2}$
$=1.75 \mathrm{~m}$
Depth of the well $(h)=10 \mathrm{~m}$
Therefore,
Inner curved surface area of the well $=2 \pi r h$
$=2 \times \frac{22}{7} \times 1.75 \times 10$
$=440 \times 0.25$
$=110 \mathrm{~m}^{2}$
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