A table-top measures $ 2 \mathrm{~m} 25 \mathrm{~cm} $ by $ 1 \mathrm{~m} 50 \mathrm{~cm} $. What is the perimeter of the table-top?
Given:
A table top measures $2\ m\ 25\ cm $ by $1\ m\ 50\ cm$.
To do:
We have to find the perimeter of the table-top.
Solution:
We know that,
Perimeter of a rectangle of length $l$ and breadth $b$ is $2(l+b)$
$1\ m=100\ cm$
This implies,
$1\ cm=\frac{1}{100}\ m$
Therefore,
Length of the table-top $(l)= 2\ m\ 25\ cm$
$= (2+\frac{25}{100})\ m$
$=(2+0.25)\ m$
$=2.25\ m$
Breadth of the table-top $(b)= 1\ m\ 50\ cm$
$= (1+\frac{50}{100})\ m$
$=(1+0.5)\ m$
$=1.05\ m$
Perimeter of the table-top $= 2 (l + b)$
$= 2 (2.25 + 1.50)\ m$
$= 2 (3.75)\ m$
$= 7.5\ m$
The perimeter of the table-top is $7.5\ m$.
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