A bus running at a speed of 18 km/h is stopped in 2.5 seconds by applying brakes. Calculate the retardation produced.

Here initial velocity $u=18\ km/h=18\times\frac{5}{18}\ m/s=5\ m/s$

Final velocity $v=0$

Time $t=2.5\ sec.$

Let $a$ be the retardation produced.

On using the equation of the motion:

$v=u+at$

$0=5+a\times2.5$

Or $2.5a=-5$

Or $a=-\frac{5}{2.5}$

Or $a=-2\ m/s^2$

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Updated on: 10-Oct-2022

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