A car of mass $2400\ kg$ moving with a velocity of $20\ ms^{-1}$ is stopped in $10\ seconds$ on applying brakes. Calculate the retardation and the retarding force.

 Here, the mass of the car $m=2400\ kg$

Initial velocity $u=20\ ms^{-1}$

Final velocity $v=0$

Time $t=10\ s$

Therefore, retardation $a=\frac{0-20}{10}$

$=-2\ m/s^2$   [-ve sign indicates the retardation]

Therefore, applied force $F=ma$

$=2400\ kg\times 2\ m/s^2$

$=4800\ N$

Therefore, the retardation of the car is $2\ m/s^2$, and the applied force is $4800\ N$.

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Updated on: 10-Oct-2022

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