A bus accelerates uniformly from 54 km/h to 72 km/h in 10 seconds Calculate the acceleration in $m/s^2$.

Here initial velocity $u=54\ km/h=54\times\frac{5}{18}=15\ m/s$

Final velocity of the bus $v=72\ km/h=72\times\frac{5}{18}=20\ m/s$

Time $t=10\ sec$

Therefore, acceleration $a=\frac{v-u}{t}$

$=\frac{20-15}{10}$

$=\frac{5}{10}\ m/s^2$

$=0.5\ m/s^2$

Therefore, the acceleration is $0.5\ m/s^2$
 

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Updated on: 10-Oct-2022

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