A bus is moving at an average speed of $46 \frac{2}{3}$ km/h. How much distance will it cover in $2 \frac{2}{5}$ hours ?

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Updated on: 10-Oct-2022

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Running At A Average Of 40 Km/Hr ,A Bus Competes A Journey In 4 $\frac{1}{2}$ Hours . How Much Time Will The Return Journey Take If The Speed Is Increased To 45 Km/Hr.
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The distance between two stations is 216 km a bus takes 4 hours to cover this distance calculate the average speed of the bus in km/hour.
Raju is moving in his car with a velocity of $50\ km/h$. How much distance will he cover in 5 minutes?
Verify:$\frac{-2}{5} + [\frac{3}{5} + \frac{1}{2}] = [\frac{-2}{5} + \frac{3}{5}] + \frac{1}{2}$
A car runs 9 kilometres using 1-litre petrol? How much distance will it cover in 3 whole $\frac{2}{3}$ litres of petrol?
Take away:(i) \( \frac{6}{5} x^{2}-\frac{4}{5} x^{3}+\frac{5}{6}+\frac{3}{2} x \) from \( \frac{x^{3}}{3}-\frac{5}{2} x^{2}+ \) \( \frac{3}{5} x+\frac{1}{4} \)(ii) \( \frac{5 a^{2}}{2}+\frac{3 a^{3}}{2}+\frac{a}{3}-\frac{6}{5} \) from \( \frac{1}{3} a^{3}-\frac{3}{4} a^{2}- \) \( \frac{5}{2} \)(iii) \( \frac{7}{4} x^{3}+\frac{3}{5} x^{2}+\frac{1}{2} x+\frac{9}{2} \) from \( \frac{7}{2}-\frac{x}{3}- \) \( \frac{x^{2}}{5} \)(iv) \( \frac{y^{3}}{3}+\frac{7}{3} y^{2}+\frac{1}{2} y+\frac{1}{2} \) from \( \frac{1}{3}-\frac{5}{3} y^{2} \)(v) \( \frac{2}{3} a c-\frac{5}{7} a b+\frac{2}{3} b c \) from \( \frac{3}{2} a b-\frac{7}{4} a c- \) \( \frac{5}{6} b c \)
The maximum speed of a train is 90 km/h. It takes 10 hours to cover a distance of 500 km. Find the ratio of its average speed to maximum speed?
Solve the following equations:$(a).\ 2y+\frac{5}{2}=\frac{37}{2}$$(b).\ 5t+28=10$$(c).\ \frac{a}{5}+3=2$$(d).\ \frac{q}{4}+7=5$$(e).\ \frac{5}{2}x=-5$$(f).\ \frac{5}{2}x=\frac{25}{4}$$(g).\ 7m+\frac{19}{2}=13$ $(h).\ 6z+10=-2$ $(i).\ \frac{3l}{2}=\frac{2}{3}$$(j).\ \frac{2b}{3}-5=3$
Simplify: $[ ( \frac{3}{2})^{-2}-( \frac{1}{3})^{2}]\times( \frac{5}{3})^{-2}$.
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