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Running At A Average Of 40 Km/Hr ,A Bus Competes A Journey In 4 $\frac{1}{2}$ Hours . How Much Time Will The Return Journey Take If The Speed Is Increased To 45 Km/Hr.
Given:
Running at an average Of 40 Km/Hr ,a bus competes a journey In 4 $\frac{1}{2}$
To do: Find how much time will the return journey will take if speed is increased to 45km/hr.
Solution:
Speed = 40 km/h
Time = 4.5 hours
Distance = Speed $\times$ Time = 40 $\times$ 4.5
Distance = 180 km
New speed = 45 km/h
Distance = 180 km
Time taken = $\frac{Distance}{ Speed}$ =$ \frac{180}{ 45}$
Time taken = 4 hours
Therefore, the return trip will be 4hours long
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