$A B C$ is a triangle, right-angled at $C$. If $A B=25$ cm and $AC=7$ cm, find $BC$.
Given :
$ABC$ is a right-angled triangle at $C$.
$AB= 25$ cm and $AC = 7$ cm.
To do :
We have to find the value of BC.
Solution :
Angle C is the right angle, this implies, AB is the hypotenuse.
Therefore,
$AB^2=AC^2 + BC^2$
$(25)^2=(7)^2+BC^2$
$BC^2 = 625 - 49$
$BC^2 = 576$
$BC^2 = 24 \times 24$
$BC = 24$ cm
The length of BC is 24 cm.
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