# Minimum Sum Path in a Triangle in C++

## Problem statement

Given a triangular structure of numbers, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below.

## Example

If input is −

   5
7 3
8 1 2
9 6 4 5

Then minimum sum is 13 as follows −

5 + 3 + 1 + 4

## Algorithm

• Use memorization technique of dynamic programming
• Create 1-D array for memorization namely memorization
• For each K row use below formula −
memorization[i] = min( memorization[i], memorization[i+1])
+ A[k][i];

## Example

Live Demo

#include <bits/stdc++.h>
using namespace std;
int getMinSum(vector<vector<int>> &arr) {
int memorization[arr.size()];
int n = arr.size() - 1;
for (int i = 0; i < arr[n].size(); ++i) {
memorization[i] = arr[n][i];
}
for (int i = arr.size() - 2; i >= 0; --i) {
for (int j = 0; j < arr[i + 1].size() - 1; ++j) {
memorization[j] = arr[i][j] +
min(memorization[j],
memorization[j + 1]);
}
}
return memorization[0];
}
int main() {
vector<vector<int>> arr = {
{5},
{7, 3},
{8, 1, 2},
{9, 6, 4, 5}, };
cout << "Minimum sum path = " << getMinSum(arr) << endl;
return 0;
}

When you compile and execute above program. It generates following output −

## Output

Minimum sum path = 13

Updated on: 20-Dec-2019

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