# Minimum Path Sum in C++

Suppose we have a m x n matrix filled with non-negative integers, find a path from top left corner to bottom right corner which minimizes the sum of all numbers along its path. Movements can only be either down or right at any point in time. So for example, if the matrix is like below

 1 3 1 1 5 1 4 2 1

The output will be 7, the path will be 1,3,1,1,1, this will minimize the sum

Let us see the steps −

• a := number of rows, b := number of columns

• i := a – 1, j := b - 1

• while j >= 0

• matrix[a, j] := matrix[a, j] + matrix[a, j + 1]

• decrease j by 1

• while i >= 0

• matrix[i, b] := matrix[i, b] + matrix[i + 1, b]

• decrease i by 1

• j := b - 1 and i := row - 1

• while i >= 0

• while j >= 0

• matrix[i, j] := matrix[i, j] + minimum of matrix[i, j + 1] and matrix[i + 1, j]

• decrease j by 1

• j := b - 1

• i := i - 1

• return matrix[0, 0]

## Example

Let us see the following implementation to get better understanding −

class Solution(object):
def minPathSum(self, grid):
"""
:type grid: List[List[int]]
:rtype: int
"""
row = len(grid)-1
column = len(grid[0])-1
i=row-1
j=column-1
while j>=0:
grid[row][j]+=grid[row][j+1]
j-=1
while i>=0:
grid[i][column]+=grid[i+1][column]
i-=1
j=column-1
i = row-1
while i>=0:
while j>=0:
grid[i][j] += min(grid[i][j+1],grid[i+1][j])
j-=1
j=column-1
i-=1
return(grid[0][0])

## Input

[[1,3,1],[1,5,1],[4,2,1]]

## Output

7

Updated on: 28-Apr-2020

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