# Maximum and Minimum in a square matrix in C++

## Problem statement

Given a square matrix of order n*n, find the maximum and minimum from the matrix

## Example

If given matrix is −

{{15, 17, 19}, {5, 1, 7}, {14, 5, 16}}
then
Minimum number is 1 and maximum number is 19

## Algorithm

• Select two elements from the matrix one from the start of a row of the matrix another from the end of the same row of the matrix
• Compare them and next compare smaller of them to the minimum of the matrix and larger of them to the maximum of the matrix.
• We can see that for two elements we need 3 compare so for traversing whole of the matrix we need total of 3/2n2 comparisons

## Example

Let us now see an example −

#include <bits/stdc++.h>
#define MAX 200
using namespace std;
void getMinMax(int matrix[MAX][MAX], int n) {
int min = INT_MAX;
int max = INT_MIN;
for (int i = 0; i < n; ++i) {
for (int j = 0; j <= n / 2; ++j){
if (matrix[i][j] > matri[i][n - j - 1]) {
if (min > matrixi][n - j - 1]) {
min = marix[i][n - j -1];
}
if (max < matrixi][j]) {
max = marix[i][j];
}
} else {
if (min > matrixi][j]) {
min = marix[i][j];
}
if (max < matrixi][n - j - 1]) {
max = marix[i][n - j - 1];
}
}
}
}
cout << "Maximum = " << max << ", Minimu = " << min << endl;
}
int main() {
int matrix[MAX][MAX] = { {15, 17, 19}, {5, 1, 7}, {14, 5, 16} };
getMinMax(matrix, 3);
return 0;
}

## Output

Maximum = 19, Minimum = 1