The length of wire PQ in case of A is equal to the diameter of the semicircle formed by the wire CDE ">

Look at figure.

The length of wire PQ in case of A is equal to the diameter of the semicircle formed by the wire CDE


The length of the wire in $(A)$ is shorter than the wire in $(B)$. So, heat will reach to pin in $(A)$ fast and the wax will melt. So, pin in $(A)$ will fall first.

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Updated on: 10-Oct-2022

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