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Jewels and Stones in Python
Suppose we have a string J that indicates some letters that are considered as Jewel, and another string S, that represents some stones that we have. Our task is to find how many of stones in S is also jewel. The letters in J and S are case sensitive. So if the J = “aZc”, and S = “catTableZebraPicnic” then there are 7 jewels.
To solve this we will convert the string into a list of characters. If the character in J present in S, then increase the count.
Example
Let us see the following implementation to get better understanding −
class Solution(object): def numJewelsInStones(self, J, S): jewels = {} for i in J: jewels[i] = 1 number = 0 for i in S: if i in jewels: number+=1 return number ob1 = Solution() print(ob1.numJewelsInStones("aZc", "catTableZebraPicnic"))
Input
"aZc" "catTableZebraPicnic"
Output
7
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