Iron powder and sulphur powder were mixed together and divided into two parts A and B. When part A was heated strongly over a burner, then a substance C was formed. The part B was, however, not heated at all. When dilute hydrochloric acid was added to substance C, then gas D was evolved and when dilute hydrochloric acid was added to part B then gas E was evolved.(a) What type of substance is B?(b) What type of substance is C?(c) Name the gas (i) D, and (ii) E?(d) State one characteristic property of gas D.(e) Write one test to identify gas E.

(a) Iron powder and sulphur powder are mixed together, hence, B is a mixture (Fe + S).

(b) Here, iron powder and sulphur powder are mixed together and heated strongly on a burner. So, C is the compound iron sulphide (FeS).

(c) (i) dilute HCl was added to C (iron sulphide) to obtain D,  hence, it is hydrogen sulphide gas.           
$FeS + 2HCl → FeCl_2 + H_2S$

(ii) When dilute HCl is added to B, Fe present in the mixture reacts with the acid to form hydrogen gas. Hence E is Hydrogen gas.
$Fe + HCl → FeCl_2 + H_2$

(d) Gas D smells like rotten egg, hence, it is hydrogen sulphide gas.           

(e) When a burning stick is held in the gas, the gas itself catches fire with a blue flame and a ‘pop’ sound. In the process, the burning stick extinguishes. Hence, E is Hydrogen gas.

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Updated on: 10-Oct-2022

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