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How to get the count of both present and absent students for a year in MySQL?
For this, you can use IF() along with aggregate function SUM(). Let us first create a table −
mysql> create table DemoTable1617 -> ( -> Attendance varchar(20), -> CurrentYear int -> ); Query OK, 0 rows affected (0.48 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable1617 values('Present',2019);
Query OK, 1 row affected (0.15 sec)
mysql> insert into DemoTable1617 values('Absent',2019);
Query OK, 1 row affected (0.20 sec)
mysql> insert into DemoTable1617 values('Absent',2017);
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable1617 values('Present',2019);
Query OK, 1 row affected (0.15 sec)
mysql> insert into DemoTable1617 values('Present',2018);
Query OK, 1 row affected (0.10 sec)
mysql> insert into DemoTable1617 values('Present',2019);
Query OK, 1 row affected (0.14 sec)Display all records from the table using select statement
mysql> select * from DemoTable1617;
This will produce the following output −
+------------+-------------+ | Attendance | CurrentYear | +------------+-------------+ | Present | 2019 | | Absent | 2019 | | Absent | 2017 | | Present | 2019 | | Present | 2018 | | Present | 2019 | +------------+-------------+ 6 rows in set (0.00 sec)
Following is the query to get the count of both present and absent students for a year
mysql> select sum(if(Attendance='Present',1,0)) as Present , -> sum(if(Attendance='Absent',1,0)) as Absent -> from DemoTable1617 -> where CurrentYear LIKE '2019%';
This will produce the following output −
+---------+--------+ | Present | Absent | +---------+--------+ | 3 | 1 | +---------+--------+ 1 row in set (0.00 sec)
Updated on: 28-Feb-2020
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